5x^2-576=0

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Solution for 5x^2-576=0 equation:



5x^2-576=0
a = 5; b = 0; c = -576;
Δ = b2-4ac
Δ = 02-4·5·(-576)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{5}}{2*5}=\frac{0-48\sqrt{5}}{10} =-\frac{48\sqrt{5}}{10} =-\frac{24\sqrt{5}}{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{5}}{2*5}=\frac{0+48\sqrt{5}}{10} =\frac{48\sqrt{5}}{10} =\frac{24\sqrt{5}}{5} $

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